If \(A = \left[ {\begin{array}{*{20}{c}} {4i - 6}&{10i}\\ {14i}&{6 + 4i} \end{array}} \right]\) and \(k = \frac{1}{{2i}}\), where \(i = \sqrt { - 1}\), then kA is equal to
1
\(\left[ {\begin{array}{*{20}{c}} {2 + 3i}&5\\ 7&{2 - 3i} \end{array}} \right]\)
2
\(\left[ {\begin{array}{*{20}{c}} {2 - 3i}&5\\ 7&{2 + 3i} \end{array}} \right]\)
3
\(\left[ {\begin{array}{*{20}{c}} {2 - 3i}&7\\ 5&{2 + 3i} \end{array}} \right]\)
4
\(\left[ {\begin{array}{*{20}{c}} {2 + 3i}&5\\ 7&{2 + 3i} \end{array}} \right]\)