If a line is perpendicular to the line 5x – y = 0 and forms a triangle of area 5 square units with co-ordinate axes, then its equation is
1
\({\rm{x}} + 5{\rm{y}} \pm 5\sqrt 2 = 0\)
2
\({\rm{x}} - 5{\rm{y}} \pm 5\sqrt 2 = 0\)
3
\(5{\rm{x}} + {\rm{y}} \pm 5\sqrt 2 = 0\)
4
\(5{\rm{x}} - {\rm{y}} \pm 5\sqrt 2 = 0\)