SSC SSC Selection Post (Phase 13) 2025 Mock Test Quantitative Aptitude Geometry Triangles, Congruence and Similarity
In triangle ABC, AB = 10 cm, AC = 12 cm, on AB, point D is taken so that BD = 5 cm and CD perpendicular to AB. DE is drawn perpendicular to AC, cutting AC in E so that quadrilateral BCED has \(\frac{2}{3}\) area of the triangle ABC. Then CE is (in cm)
1
10
2
6
3
12
4
8