SSC SSC Selection Post (Phase 13) 2025 Mock Test Quantitative Aptitude Geometry Triangles

In a Δ EFG, EH is the angle bisector of ∠FEG and EK ⊥ FG. Also, ∠EFK = 60∘  and ∠EGH = 30∘. Then find the value of ∠EHK. 

1
45∘ 
2
75∘ 
3
25∘ 
4
30∘ 
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