If a man covers \(\frac{4}{5}^{\rm th}\) part of a circular track in m minutes, at the same rate, how many minutes does he take to complete one revolution around the entire track?
1
\(\frac{4 m}{4}\) minutes
2
\(\frac{4 m}{5}\) minutes
3
\(\frac{5m }{4}\) minutes
4
\(\frac{m}{4}\) minutes