Let us consider an initial value problem y' = xy1/3, y(0) = 0, (x, y) ∈ ℝ × ℝ. Then which of the following is correct?
1
The function f(x, y) = xy1/3 does not satisfy the Lipschitz conditions with respect to y in any neighbourhood of y = 0
2
The IVP has no solution
3
The IVP has unique solution
4
The IVP has more than one solution