Engineering Mathematics Probability and Statistics Random Variables Basics

Let x ~ Binomial (5,0.6) and Y ~ Poisson (2) be independent. Then P(xy = 0) equals:

1

e^-2. (0.4)⁵

2

e^-2 + (0.4)⁵

3

e^-2+ (0.4)⁵ - e^-2. (0.4)⁵

4

e-2 + (0.6)5 + (1 - e^-2) (0.4)5

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