If the value of the approximate solution of the initial value problem  

\(\rm \left\{\begin{matrix}y'(x)=x(y(x)+1), &x\in R\\\ y(0)=β \end{matrix}\right.\)

at x = 0.2 using the forward Euler method with step size 0.1 is 1.02, then the value of β is 

1
0
2
-1
3
2
4
1

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