The value of λ for which the integral equation 

\(y(x)=\lambda \displaystyle \int_0^1 x e^{x+2t} y(t) d t\)

has a non-zero solution, is

1
\(\frac{7}{2e^2+1}\)
2
\(\frac{9}{2e^3+1}\)
3
\(\frac{4}{e^3+1}\)
4
\(\frac{1}{3e^2+1}\)

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