The value of \(\left({ {1 - \cotθ} \over 1 - \tanθ}\right)^2\) - 1 when 0° < θ < 90°, (θ ≠ 0)is equal to:

1
cos2θ- 1
2
secθ + 1
3
cot2​ θ - 1 
4
sinθ - 1

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation