The sum of n term of the series
1 + 9 + 24 + 46 + 75 + ...... to n terms is equal to:
1
\(\frac{n(n + 1)(5n - 4)}{6}\)
2
\(\frac{n(n + 1)(3n - 4)}{6}\)
3
\(\frac{n(n - 1)(7n + 4)}{6}\)
4
\(\frac{n(n + 1)(7n - 4)}{6}\)
The sum of n term of the series
1 + 9 + 24 + 46 + 75 + ...... to n terms is equal to: