In a quadrilateral ABCD, with unequal sides if the diagonals AC and BD intersect at right angles, then.

1
AB2 + BC2 = CD2 + DA2
2
AB2 + AD2 = BC2 + CD2
3
AB2 + CD2 = BC2 + DA2
4
AB2 + BC2 = 2(CD2 + DA2)

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