If Sn is the sum of the first n terms of the series 12 + 2 × 22 + 32 + 2 × 42 + 52 + 2 × 62 + .... ∞, then, when n is even Sn =

1
\(\frac{n(n+1)}{2}\)
2
\(\frac{n^2(n+1)}{2}\)
3
\(\frac{n(n+1)}{2}^2\)
4
\(\frac{n^2(n+2)}{2}\)

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