\(\rm \frac{3}{1!}+\frac{5}{3!}+\frac{7}{5!}+\frac{9}{7!}+...\) is equal to

1
e
2
\(\rm \frac{3e-e^{-1}}{2}\)
3
\(\rm \frac{3e+e^{-1}}{2}\)
4
\(\rm \frac{3e}{2}\)

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