Mathematics Three Dimensional Geometry Angle with Planes

If the angle between the line \(2(x+1)=y=z+4\) and the plane \(2x-y+\sqrt{\lambda}z+4=0\) is \(\dfrac{\pi}{6}\), then the value of \(\lambda\) is :

1
\(\frac{135}{7}\)
2
\(\frac{45}{11}\)
3
\(\frac{45}{7}\)
4
\(\frac{135}{11}\)

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