Two condensers C1 & C2 in a circuit are joined as shown in the figure. The potential of point A is V1 and that of point B is V2. The potential at point D will be
1
\(\rm \frac{1}{2}(V_1+V_2)\)
2
\(\rm \frac{C_2V_1+C_1V_2}{C_1+C_2}\)
3
\(\rm \frac{C_1V_1+C_2V_2}{C_1+C_2}\)
4
\(\rm \frac{C_2V_1-C_1V_2}{C_1+C_2}\)