For \(I=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]\), if \(A=\left[\begin{array}{cc}a & b \\ c & -a\end{array}\right]\) be such that A= I, then:

1
1 + a+ bc = 0
2
1 - a- bc = 0
3
1 - a+ bc = 0
4
1 + a- bc = 0

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