For \(x \in \mathbb{R}, x \neq 0, x \neq 1\), let \(f_{0}(x) = \dfrac {1}{1 - x}\) and \(f_{n + 1} (x) = f_{0} (f_{n}(x)), n = 0, 1, 2, \ldots\). Then the value of \(f_{100}(3) + f_{1}\left ( \dfrac {2}{3} \right ) + f_{2} \left ( \dfrac {3}{2} \right )\) is equal to:
1
\( \dfrac {1}{3} \)
2
\( \dfrac {4}{3} \)
3
\( \dfrac {8}{3} \)
4
\( \dfrac {5}{3} \)