A cannon on a level plane is aimed at an angle \( \theta \) above the horizontal and a shell is fired with a muzzle velocity \( v_0 \) towards a vertical cliff a distance \( D \) away. Then the height from the bottom at which the shell strikes the side wall of the cliff is
1
\( D \sin \theta - \dfrac{gD^2}{2v_0^2 \sin^2 \theta} \)
2
\( D \cos \theta - \dfrac{gD^2}{2v_0^2 \cos^2 \theta} \)
3
\( D \tan \theta - \dfrac{gD^2}{2v_0^2 \cos^2 \theta} \)
4
\( D \tan \theta - \dfrac{gD^2}{2v_0^2 \sin^2 \theta} \)