If \(\frac{{\sqrt {3 + x} + \sqrt {3 - x} }}{{\sqrt {3 + x} - \sqrt {3 - x} }} = 2\), then \(x + \frac{1}{x}\) is equal to:

1
\(\frac{{143}}{{60}}\)
2
\(\frac{{153}}{{50}}\)
3
\(\frac{{169}}{{60}}\)
4
\(\frac{{144}}{{81}}\)

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