For the equation f(x) = x2 – x – 1 = 0, a root lies between 1 and 2. The root of equation at second interval by bisection method is
1
1.51
2
2
3
1.66
4
1.75
For the equation f(x) = x2 – x – 1 = 0, a root lies between 1 and 2. The root of equation at second interval by bisection method is