Teaching DSSSB TGT Mock Test 2025 Engineering Mathematics Combinatorics Summation

\(\sum_{x=1}^n\) x(x + 2)(x + 4) is equal to 

1
\(\frac{n(n+1)(n+4)}{3}\)
2
\(\frac{n(n+1)(n+4)(n+5)}{4}\)
3
\(\frac{n(n-1)(n+4)}{4}\)
4
\(\frac{n(n+1)(n+2)(n+3)}{4}\)
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