As x increased from – 3 to 3, the function
\(f\left( x \right) = \frac{{{e^x}}}{{1 + {e^x}}}\)
1
monotonically increases
2
monotonically decreases
3
increases to a maximum value and then decreases
4
decrease to a minimum value and then increases
As x increased from – 3 to 3, the function
\(f\left( x \right) = \frac{{{e^x}}}{{1 + {e^x}}}\)