If A = \(\rm 4u^2 \overrightarrow{i}−u^3 \overrightarrow{j}+u \overrightarrow{k}\) and B = \(\rm 2 \overrightarrow{i}−u \overrightarrow{k}\) are vector functions of scalar variable u, then the derivative of A × B is:
1
\(\rm u^3 \overrightarrow{i}+12 u^2 \overrightarrow{j}\)
2
\(\rm 3u^2 \overrightarrow{j}+2 u \overrightarrow{k}\)
3
\(\rm 4u^3\overrightarrow{i}+\left(12 u^2+2\right) \overrightarrow{j}+6 u^2 \overrightarrow{k} \)
4
14u − 3u2