Find the general solution of given equation \(\frac{\text{dy}}{\text{dx}}=\text{ }\!\!~\!\!\text{ }-3\text{x}{{\text{y}}^{3}}\) given that x > 0?
1
\(\frac{1}{3{{y}^{2}}}-\frac{3}{2}{{x}^{2}}+c=0\)
2
\(\frac{1}{{\;{y^2}}} - \frac{3}{2}{x^2}--c = 0\)
3
\(\frac{1}{{2\;{y^2}}} - \frac{3}{2}{x^2} + c = 0\)
4
None of the above