Let y = y(x) be the solution of the differential equation

(x2 + 4)2dy + (2x3y + 8xy – 2)dx = 0. If y(0) = 0, then y(2) is equal to   

1
\(\frac{\pi}{8}\)
2
\(\frac{\pi}{16}\)
3
2π 
4
\(\frac{\pi}{32}\)

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