You are given that A and B are two events such that P(B) = \(\frac{3}{5}\), P(A ∣ B) = \(\frac{1}{2}\) and P(A ∪ B) = \(\frac{4}{5}\) , then P(B ∣ A') is equal to

1
\(\frac{1}{5}\)
2
\(\frac{3}{10}\)
3
\(\frac{1}{2}\)
4
\(\frac{3}{5}\)

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