Teaching DSSSB TGT Mock Test 2025 Mathematics Differential Calculus Applications of Derivatives

The slope of tangent to the curve x = t2 + 3t – 8, y = 2t2 – 2t – 5 at the point (2, –1) is:

1
\(\frac{22}{7}\)
2
\(\frac{6}{7}\)
3
\(\frac{-6}{7}\)
4
–6
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