Let f: [1, ∞ ]→ [2, ∞] be a differentiable function such that f(1) = 2. If \( 6\displaystyle\int^x_1 f(t)dt=3x\ f(x)-x^3-5\), Ɐ x ≥ 1 then the value of f(2) is:

1
6
2
4
3
\(\frac{1}{4}\)
4
\(\frac{1}{6}\)

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