Consider an objective function Z(x, y) = 5x + 3y
And the constraints:
3x + 5y ≤ 15
5x + 2y ≤ 10
x ≥ 0, y ≥ 0
The maximum value of Z occurs at
1
\(\left ( \frac{13}{19},\frac{55}{19} \right )\)
2
\(\left ( \frac{3}{19},\frac{5}{19} \right )\)
3
\(\left ( \frac{20}{19},\frac{45}{19} \right )\)
4
\(\left ( \frac{34}{19},\frac{56}{19} \right )\)