The general solution of the differential equation (1 + y2) dx = (tan-1 y - x) dy is

1
x = (tan-1 y) - 1 + \(\rm C e^{-tan^{-1}y}\)
2
x = (tan-1 y) - 1 + \(\rm C e^{tan^{-1}y}\)
3
x = (tan-1 y) - 1 + C
4
x = (tan-1 y) + \(\rm C e^{-tan^{-1}y}\)

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