Find the directrix of hyperbola \(\frac{x^2}{9}-\frac{y^2}{4} = 1\) is:

1
x = \(\pm \frac{9}{\sqrt{13}}\)
2
x = \(\pm \frac{6}{\sqrt 13}\)
3
y = \(\pm \frac{6}{\sqrt{13}}\) 
4
y = 0

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