Teaching DSSSB TGT Mock Test 2025 Mathematics Differential Equations Solution of Differential Equations
Solve the initial value problem, dy = ex + 2y dx , y (0) = 0.
1
y = \(\rm \frac{1}{2}\left ( \frac{1}{3+2\ e^{x}} \right )\)
2
y = \(\rm \left ( \frac{1}{3- 2\ e^{x}} \right )\)
3
y = \(\rm \frac{1}{2}\ln\left ( \frac{1}{3- 2\ e^{x}} \right )\)
4
y = 3 - 2ex