If n harmonic means are inserted between 1 and r, then \(\frac{{{1^{st}}mean}}{{{n^{th}}mean}} = \)

1
\(\frac{{n + r}}{{nr - 1}}\)
2
\(\frac{{2n + r}}{{nr - 1}}\)
3
\(\frac{{n - r}}{{nr + 1}}\)
4
\(\frac{{n + r}}{{nr + 1}}\)

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