The value of \(\int_c \frac{z^2-4}{z\left(z^2+9\right)}\)is where C is a circle |z| = 1,

1
\(\frac{-2 \pi i}{9}\)
2
\(\frac{-4 \pi i}{9}\)
3
\(\frac{-8 \pi i}{9}\)
4
none of these

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