Mathematics Three Dimensional Geometry Equation of a Line

Let the line \(\frac{{x - 1}}{2} = \frac{{y + 2}}{{ - 3}} = \frac{{z - 3}}{4}\) lie in the plane x - y + az + b = 0 The value of b - a is 

1
1
2
-1
3
2
4
\(\frac{3}{4}\)

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