For A = \(\left[ {\begin{array}{*{20}{c}} 2&4\\ {0}&3 \end{array}} \right]\), then A-1 is given by :
1
\(\left[ {\begin{array}{*{20}{c}} 3&{ -4}\\ 0&2 \end{array}} \right]\)
2
\(6\left[ {\begin{array}{*{20}{c}} 3&{ -4}\\ 0&2 \end{array}} \right]\)
3
\(\frac 16 \left[ {\begin{array}{*{20}{c}} 3&{ -4}\\ 0&2 \end{array}} \right]\)
4
\(\frac 16 \left[ {\begin{array}{*{20}{c}} 2&4\\ {0}&3 \end{array}} \right]\)