If \(\rm \left( \frac{x}{x+1} \right)^2 -5 \left( \frac{x}{x+1} \right) +6=0\), then the value of \(\rm \left( 1+\frac{1}{x} \right) \) is equal to :

1
- 5
2
6
3
\(\rm1 \frac{1}{6}\ or \ 1\frac{1}{5}\)
4
\(\rm \frac{1}{2}\ or \ \frac{1}{3}\)

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