The value of b2 in order that the foci of the hyperbola \(\rm \frac{x^2}{144}-\frac{y^2}{81}=\frac{1}{25}\) and the ellipse \(\rm \frac{x^2}{16}+\frac{y^2}{b^2}=1\) coincide is 

1
1
2
5
3
7
4
9

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation