If 2 tan θ = 3, then \(\frac{(3 sin θ - 2 cos θ)}{(3 sin θ + 2 cos θ)}\) is equal to:

1
\(\frac{6}{13}\)
2
\(\frac{6}{7}\)
3
\(\frac{5}{7}\)
4
\(\frac{5}{13}\)

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