A calorimeter contains 100 g of water at 25°C. Some amount of ice initially at -20° C is dropped in it and one-fourth of the ice has melted till the equilibrium is reached. If the amount of ice dropped was 1.5 times the water equivalent of the calorimeter, then the water equivalent of the calorimeter is - (Take sw = 1 cal/g°C, sice = 0.5 cal/g°C and Lf of ice = 80 cal/g)