A ball of mass ‘m’ is projected from the origin of co-ordinates with a velocity ‘u’ making an angle θ with the horizontal. At the point (α, β) on the plane of the trajectory of the particle, the total mechanical energy of the ball will be:
1
\(\frac{1}{2}m{u^2}{\sin ^2}\theta \frac{\alpha }{\beta }\)
2
\(\frac{1}{2}m{u^2}{\cos ^2}\theta \frac{\alpha }{\beta }\)
3
\(\frac{1}{2}m{u^2}\)
4
\(\frac{1}{2}m{u^2}{\cos ^2}\theta \)