\(\sum\limits_{n = 1}^\infty {\frac{{{{\left[ {\left( {n + 1} \right)x} \right]}^n}}}{{{n^{n + 1}}}}} \) is
1
Divergent |x| < 1
2
Convergent |x| ≥ 1
3
Divergent at x = -2
4
Convergent if |x| < 1 and Divergent |x| ≥ 1
\(\sum\limits_{n = 1}^\infty {\frac{{{{\left[ {\left( {n + 1} \right)x} \right]}^n}}}{{{n^{n + 1}}}}} \) is