Teaching UP TGT Mock Test Series 2025 Mathematics Integral Calculus Application of Integrals

What is the area of the region (in the first quadrant) bounded by y = \(\sqrt{1−\text{x}^2}\), y = x and y = 0 ?

1
\(\frac{\pi}{4}\)
2
\(\frac{\pi}{6}\)
3
\(\frac{\pi}{8}\)
4
\(\frac{\pi}{12}\)
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