If \(\left| {\begin{array}{*{20}{c}} {6i}&{ - 3i}&1\\ 4&{3i}&{ - 1}\\ {20}&3&i \end{array}} \right| = x + iy,\;then\;\left( {x,y} \right)is\)

1
(3, 1)
2
(1, 3)
3
(0, 3)
4
(0, 0)

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