If f'(x) = x + 1/x, then 𝑓(π‘₯) isΒ Β 

1
x2 + log |x|Β + C
2
\(\frac{x^2}{2}\)Β + log |x| + C
3
\(\frac{1}{x}\)Β + log |x| + C
4
\(\frac{1}{x}\)Β - log |x| + C

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