\(^{235}_{92}U\rightarrow^{207}_{84}Pb+6^{0}_{-1}\beta+X^{4}_{2}\alpha\)
In the above reaction, The value of X will be:
1
10
2
9
3
8
4
7
\(^{235}_{92}U\rightarrow^{207}_{84}Pb+6^{0}_{-1}\beta+X^{4}_{2}\alpha\)
In the above reaction, The value of X will be: