If \(\vec{a} = 4\hat{j}\) and \(\vec{b} = 3\hat{j} + 4\hat{k}\), then the vector form of the component of \(\vec{a}\) along \(\vec{b}\) is

1
\(\dfrac{12}{10\sqrt{3}}(3\hat{j}+4\hat{k})\)
2
\(\rm \dfrac {12}{25}(3\vec j + 4 \vec k)\)
3
\(\dfrac{12}{\sqrt{13}}(3\hat{j}+4\hat{k})\)
4
\((3\hat{j}+4\hat{k})\)

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