Find the equation of family of circles which are passing through the intersection of two circles S1: x2 + y2 - 4 = 0 and S2: x2 + y2 - 2x - 4y + 4 = 0 ?

1
(1 + λ) x2 + (1 + λ) y2 + 2λx - 4λy + (4λ - 4) = 0
2
(1 + λ) x2 + (1 + λ) y2 + 2λx + 4λy + (4λ - 4) = 0
3
(1 + λ) x2 + (1 + λ) y2 - 2λx - 4λy - (4λ - 4) = 0
4
(1 + λ) x2 + (1 + λ) y2 - 2λx - 4λy + (4λ - 4) = 0

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