The solution at (x, t) = (2, 1) of the partial differential equation, \(\frac{\partial^2u}{\partial t^2}=36\frac{\partial^2 u}{\partial x^2}\) subject to initial condition of u(x, 0) = 5x and \(\frac{\partial u}{\partial t}(x,\;0)\) = 1 

1
7
2
11
3
21
4
31

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation